Pulse Math

• Peak Current is the current output of the pulse power supply during the On Time. Current outputs for our pulse power supplies are set using peak current.
• Peak Voltage is the voltage output of the pulse power supply during the On Time. Voltage outputs for our power supplies are set using peak voltages.
• On Time is the portion of time the pulse power supply has current and/or voltage output.
  
• Off Time is the portion of time the pulse power supply has zero current and/or voltage output.
  
• Average Current is the comparative value of Direct Current. (DC) Current meter readings for our power supplies read back in average current.
  
• Average Voltage is the comparative value of a steady voltage. Voltage meter readings for our power supplies read back in average voltage.
  
• Average Current = Duty Cycle x Peak Current
  
• Average Voltage = Duty Cycle x Peak Voltage
  
• Duty Cycle = On Time / (On Time + Off Time)
  
• Frequency = 1 / (On Time + Off Time) {assuming neither On Time or Off Time = 0}

1 division = 1 ms

In this example, the On Time = 9 ms, the Off Time = 5 ms.
Duty Cycle = 9ms / (9ms + 5ms) = 9/14 = 0.643 = 64.3%
Frequency = 1 / (9ms + 5ms) = 1 / 14ms = 71.4Hz
If the peak current output was 0.5 amps, the average current output would be:
Average Current = 0.643 x 0.5 amps = 0.321 amps.
If the peak voltage output was 2 volts, the average voltage output would be:
Average Voltage = 0.643 x 2 volts = 1.286 volts.

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